Questions: Problem 10: The weights of newborn babies in a certain region follow a normal distribution with a mean of 7.5 pounds and a standard deviation of 1.2 pounds. What is the probability that a randomly selected baby weighs between 6 and 9 pounds?
Transcript text: Problem 10: The weights of newborn babies in a certain region follow a normal distribution with a mean of 7.5 pounds and a standard deviation of 1.2 pounds. What is the probability that a randomly selected baby weighs between 6 and 9 pounds?
Solution
Solution Steps
Step 1: Define the Normal Distribution Parameters
The weights of newborn babies in the region follow a normal distribution characterized by a mean (\( \mu \)) of 7.5 pounds and a standard deviation (\( \sigma \)) of 1.2 pounds.
Step 2: Calculate the Cumulative Distribution Function (CDF) at 9 Pounds
To find the probability that a randomly selected baby weighs less than or equal to 9 pounds, we compute the CDF at \( x = 9 \):
\[
P(X \leq 9) = CDF(9) \approx 0.8944
\]
Step 3: Calculate the Cumulative Distribution Function (CDF) at 6 Pounds
Next, we calculate the CDF at \( x = 6 \):
\[
P(X \leq 6) = CDF(6) \approx 0.1056
\]
Step 4: Determine the Probability of Weighing Between 6 and 9 Pounds
The probability that a randomly selected baby weighs between 6 and 9 pounds is given by the difference of the two CDF values:
\[
P(6 < X < 9) = P(X \leq 9) - P(X \leq 6) \approx 0.8944 - 0.1056 = 0.7887
\]
Final Answer
The probability that a randomly selected baby weighs between 6 and 9 pounds is approximately
\[
\boxed{0.7887}
\]