Questions: Consider the following. Function Slope ------ y=x^2+8x m=-10 Determine the point(s), if any, at which the graph of the given function has a tangent line with the given slope. (If an answer does not exist, leave the space blank.)

Consider the following.

Function  Slope
------
y=x^2+8x  m=-10

Determine the point(s), if any, at which the graph of the given function has a tangent line with the given slope. (If an answer does not exist, leave the space blank.)
Transcript text: sider the following. \begin{tabular}{|c|c|} \hline Function & Slope \\ \hline$y=x^{2}+8 x$ & $m=-10$ \\ \hline \end{tabular} rmine the point(s), if any, at which the graph of the given function has a tangent line with the given slope. (If an answer does not \[ =(\square) \] $\square$
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Solution

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Solution Steps

To determine the point(s) at which the graph of the function \( y = x^2 + 8x \) has a tangent line with a given slope \( m = -10 \), we need to follow these steps:

  1. Find the derivative of the function \( y = x^2 + 8x \) to get the slope of the tangent line at any point \( x \).
  2. Set the derivative equal to the given slope \( m = -10 \) and solve for \( x \).
  3. Substitute the \( x \) value(s) back into the original function to find the corresponding \( y \) value(s).
Step 1: Find the Derivative of the Function

Given the function \( y = x^2 + 8x \), we first find its derivative to determine the slope of the tangent line at any point \( x \).

\[ \frac{dy}{dx} = 2x + 8 \]

Step 2: Set the Derivative Equal to the Given Slope

We are given that the slope of the tangent line is \( m = -10 \). We set the derivative equal to this slope and solve for \( x \).

\[ 2x + 8 = -10 \]

Solving for \( x \):

\[ 2x = -18 \implies x = -9 \]

Step 3: Find the Corresponding \( y \) Value

Substitute \( x = -9 \) back into the original function to find the corresponding \( y \) value.

\[ y = (-9)^2 + 8(-9) = 81 - 72 = 9 \]

Final Answer

\[ \boxed{(-9, 9)} \]

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