Questions: The Mars company says that before the introduction of purple, yellow candies made up 20% of their plain MM's, red another 20%, and orange, blue, and green each made up 10%. The rest were brown. Complete parts a and b.
1. What is the probability that this MM is blue?
2. What is the probability that this MM is green or brown?
3. What is the probability that this MM is not red?
4. What is the probability that this MM is spotted?
1. The probability that the MM is blue is .1.
2. The probability that the MM is green or brown is 4.
3. The probability that the MM is not red is 80.
4. The probability that the MM is spotted is.
Transcript text: The Mars company says that before the introduction of purple, yellow candies made up 20% of their plain M&M's, red another 20%, and orange, blue, and green each made up 10%. The rest were brown. Complete parts a and b.
1. What is the probability that this M&M is blue?
2. What is the probability that this M&M is green or brown?
3. What is the probability that this M&M is not red?
4. What is the probability that this M&M is spotted?
1. The probability that the M&M is blue is .1.
2. The probability that the M&M is green or brown is 4.
3. The probability that the M&M is not red is 80.
4. The probability that the M&M is spotted is.
Solution
Solution Steps
To solve the given questions, we need to use the probabilities provided for each color of M&M's. The total probability must sum up to 1 (or 100%).
The probability that an M&M is blue is directly given as 10%.
To find the probability that an M&M is green or brown, we need to add the probabilities of green and brown M&M's.
To find the probability that an M&M is not red, we subtract the probability of red M&M's from 1.
Step 1: Probability of Blue M&M
The probability that an M&M is blue is given by:
\[
P(\text{Blue}) = 0.1
\]
Step 2: Probability of Green or Brown M&M
To find the probability that an M&M is either green or brown, we sum the probabilities of green and brown:
\[
P(\text{Green}) = 0.1
\]
\[
P(\text{Brown}) = 1 - (P(\text{Yellow}) + P(\text{Red}) + P(\text{Orange}) + P(\text{Blue}) + P(\text{Green})) = 1 - (0.2 + 0.2 + 0.1 + 0.1 + 0.1) = 0.3
\]
Thus,
\[
P(\text{Green or Brown}) = P(\text{Green}) + P(\text{Brown}) = 0.1 + 0.3 = 0.4
\]
Step 3: Probability of Not Red M&M
The probability that an M&M is not red is calculated as:
\[
P(\text{Not Red}) = 1 - P(\text{Red}) = 1 - 0.2 = 0.8
\]
Final Answer
The probabilities are as follows:
Probability that the M&M is blue: \( \boxed{0.1} \)
Probability that the M&M is green or brown: \( \boxed{0.4} \)
Probability that the M&M is not red: \( \boxed{0.8} \)