To rationalize the denominator of the expression
\[ \frac{\sqrt{x}}{\sqrt{x}+\sqrt{a}}, \]
we multiply both the numerator and the denominator by the conjugate of the denominator, which is \(\sqrt{x} - \sqrt{a}\). This gives us:
\[ \frac{\sqrt{x}(\sqrt{x} - \sqrt{a})}{(\sqrt{x}+\sqrt{a})(\sqrt{x}-\sqrt{a})}. \]
Next, we simplify the expression. The denominator simplifies using the difference of squares:
\[ (\sqrt{x}+\sqrt{a})(\sqrt{x}-\sqrt{a}) = x - a. \]
Thus, the expression becomes:
\[ \frac{\sqrt{x}(\sqrt{x} - \sqrt{a})}{x - a}. \]
The numerator can be expressed as:
\[ \sqrt{x}(\sqrt{x} - \sqrt{a}) = x - \sqrt{a}\sqrt{x}. \]
Therefore, the fully simplified expression is:
\[ \frac{x - \sqrt{a}\sqrt{x}}{x - a}. \]
The rationalized form of the expression \(\frac{\sqrt{x}}{\sqrt{x}+\sqrt{a}}\) is
\[ \boxed{\frac{x - \sqrt{a}\sqrt{x}}{x - a}}. \]
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