Questions: On Tuesday, a local hamburger shop sold a combined total of 321 hamburgers and cheeseburgers. The number of cheeseburgers sold was two times the number of hamburgers sold. How many hamburgers were sold on Tuesday? hamburgers

Solution Steps

To solve this problem, we can set up a system of equations based on the information given. Let \( h \) represent the number of hamburgers sold and \( c \) represent the number of cheeseburgers sold. We know that the total number of hamburgers and cheeseburgers sold is 321, and the number of cheeseburgers sold is twice the number of hamburgers sold. This gives us two equations:

1. \( h + c = 321 \)
2. \( c = 2h \)

We can substitute the second equation into the first to solve for \( h \).

Let \( h \) represent the number of hamburgers sold and \( c \) represent the number of cheeseburgers sold. We are given the following information:

1. The total number of hamburgers and cheeseburgers sold is 321.
2. The number of cheeseburgers sold is twice the number of hamburgers sold.

This gives us the system of equations: \[ h + c = 321 \] \[ c = 2h \]

Substitute \( c = 2h \) into the first equation: \[ h + 2h = 321 \] \[ 3h = 321 \] Solve for \( h \): \[ h = \frac{321}{3} = 107 \]

Final Answer