Questions: A process is observed in two different regions, one with higher rate of activation and the other 10 times lower. During the higher rate of activation in the first region, particles are detected. What fraction of particles would you expect to observe in the region with the 10 times lower rate of activation?

$A process is observed in two different regions, one with higher rate of activation and the other 10 times lower. During the higher rate of activation in the first region, particles are detected. What fraction of particles would you expect to observe in the region with the 10 times lower rate of activation?$

Transcript text: A process is observed in two different regions, one with higher rate of activation and the other 10 times lower. During the higher rate of activation in the first region, particles are detected. What fraction of particles would you expect to observe in the region with the 10 times lower rate of activation?

Solution

Solution Steps

Step 1: Identify the given information

The store bought milk for $2.30 per half gallon.
The store sold the milk for $4.40 per half gallon.
The store made a profit of $100.60.

Step 2: Define the variables

Let $ x $ be the number of half gallons of milk sold.

Step 3: Set up the equation

The profit made per half gallon is the selling price minus the buying price: \[ \text{Profit per half gallon} = 4.40 - 2.30 = 2.10 \]

The total profit is given by: \[ \text{Total profit} = \text{Profit per half gallon} \times \text{Number of half gallons sold} \] \[ 100.60 = 2.10 \times x \]

Step 4: Solve for $ x $

\[ x = \frac{100.60}{2.10} \] \[ x = 47.9047619 \]

Since the number of half gallons must be a whole number, we round to the nearest whole number: \[ x \approx 48 \]