Questions: The first row has been completed for you. atom subshell from which electron removed to form +1 cation subshell to which electron added to form -1 anion --------- H 1 s 1 s He P Ar

The first row has been completed for you.

atom subshell from which electron removed to form +1 cation subshell to which electron added to form -1 anion
---------
H 1 s 1 s
He
P
Ar

Transcript text: The first row has been completed for you. \begin{tabular}{|c|c|c|} \hline atom & \begin{tabular}{c} subshell from which electron \\ removed to form +1 cation \end{tabular} & \begin{tabular}{c} subshell to which electron \\ added to form -1 anion \end{tabular} \\ \hline H & 1 s & 1 s \\ \hline He & $\square$ & $\square$ \\ \hline P & $\square$ & $\square$ \\ \hline Ar & $\square$ & $\square$ \\ \hline \end{tabular}

Solution

Solution Steps

Step 1: Determine the subshell for He to form a +1 cation

Helium (He) has an electron configuration of $1s^2$. To form a +1 cation, one electron is removed from the outermost subshell, which is the $1s$ subshell.

Step 2: Determine the subshell for He to form a -1 anion

Helium (He) is a noble gas with a full $1s$ subshell. Adding an electron to form a -1 anion would involve adding an electron to the next available subshell, which is $2s$.

Step 3: Determine the subshell for P to form a +1 cation

Phosphorus (P) has an electron configuration of $1s^2 2s^2 2p^6 3s^2 3p^3$. To form a +1 cation, one electron is removed from the outermost subshell, which is the $3p$ subshell.

Step 4: Determine the subshell for P to form a -1 anion

To form a -1 anion, an electron is added to the outermost subshell of phosphorus, which is the $3p$ subshell.

Step 5: Determine the subshell for Ar to form a +1 cation

Argon (Ar) has an electron configuration of $1s^2 2s^2 2p^6 3s^2 3p^6$. To form a +1 cation, one electron is removed from the outermost subshell, which is the $3p$ subshell.

Step 6: Determine the subshell for Ar to form a -1 anion

Argon (Ar) is a noble gas with a full $3p$ subshell. Adding an electron to form a -1 anion would involve adding an electron to the next available subshell, which is $4s$.

Final Answer

\[ \begin{array}{|c|c|c|} \hline \text{atom} & \begin{array}{c} \text{subshell from which electron} \\ \text{removed to form +1 cation} \end{array} & \begin{array}{c} \text{subshell to which electron} \\ \text{added to form -1 anion} \end{array} \\ \hline \text{H} & 1s & 1s \\ \hline \text{He} & 1s & 2s \\ \hline \text{P} & 3p & 3p \\ \hline \text{Ar} & 3p & 4s \\ \hline \end{array} \]

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