Questions: One of the student's results is given below. Pressure = 1.6 x 10^5 Pa volume = 9.0 cm^3 Calculate the volume of the gas when the pressure was 1.8 x 10^5 Pa. The temperature of the gas was constant. [3 marks] Volume = cm^3

Solution Steps

We are given the initial pressure \( P_1 \) and volume \( V_1 \) of the gas: \[ P_1 = 1.6 \times 10^5 \, \text{Pa} \] \[ V_1 = 9.0 \, \text{cm}^3 \]

We are also given the final pressure \( P_2 \): \[ P_2 = 1.8 \times 10^5 \, \text{Pa} \]

Since the temperature of the gas is constant, we can use Boyle's Law, which states: \[ P_1 V_1 = P_2 V_2 \]

Rearrange the equation to solve for \( V_2 \): \[ V_2 = \frac{P_1 V_1}{P_2} \]

Substitute the given values into the equation: \[ V_2 = \frac{(1.6 \times 10^5 \, \text{Pa}) \times (9.0 \, \text{cm}^3)}{1.8 \times 10^5 \, \text{Pa}} \]

Perform the calculation: \[ V_2 = \frac{1.44 \times 10^6 \, \text{Pa} \cdot \text{cm}^3}{1.8 \times 10^5 \, \text{Pa}} = 8.0 \, \text{cm}^3 \]

Final Answer