Questions: One of the student's results is given below. Pressure = 1.6 x 10^5 Pa volume = 9.0 cm^3 Calculate the volume of the gas when the pressure was 1.8 x 10^5 Pa. The temperature of the gas was constant. [3 marks] Volume = cm^3

Solution Steps

We are given the initial pressure $P_1$ and volume $V_1$ of the gas: $$P_1 = 1.6 \times 10^5 \, \text{Pa}$$ $$V_1 = 9.0 \, \text{cm}^3$$

We are also given the final pressure $P_2$: $$P_2 = 1.8 \times 10^5 \, \text{Pa}$$

Since the temperature of the gas is constant, we can use Boyle's Law, which states: $$P_1 V_1 = P_2 V_2$$

Rearrange the equation to solve for $V_2$: $$V_2 = \frac{P_1 V_1}{P_2}$$

Substitute the given values into the equation: $$V_2 = \frac{(1.6 \times 10^5 \, \text{Pa}) \times (9.0 \, \text{cm}^3)}{1.8 \times 10^5 \, \text{Pa}}$$

Perform the calculation: $$V_2 = \frac{1.44 \times 10^6 \, \text{Pa} \cdot \text{cm}^3}{1.8 \times 10^5 \, \text{Pa}} = 8.0 \, \text{cm}^3$$

Final Answer