Questions: Find an equation in the form of y=f(x) for the graph sketched below. Use base 2 for any logarithmic or exponential functions.

Find an equation in the form of y=f(x) for the graph sketched below. Use base 2 for any logarithmic or exponential functions.
Transcript text: Find an equation in the form of $y=f(x)$ for the graph sketched below. Use base 2 for any logarithmic or exponential functions.
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Solution

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Solution Steps

Step 1: Identify the Type of Function

The graph appears to be an exponential function because it shows rapid growth as \( x \) increases and approaches a horizontal asymptote as \( x \) decreases.

Step 2: Determine the Horizontal Asymptote

The horizontal asymptote is at \( y = 5 \). This suggests that the function has been shifted vertically by 5 units.

Step 3: Identify a Point on the Graph

A point on the graph is \((0, 6)\). This point will help us determine the specific parameters of the exponential function.

Step 4: Formulate the General Equation

The general form of an exponential function with a horizontal asymptote at \( y = 5 \) is: \[ y = a \cdot 2^{bx} + 5 \]

Step 5: Solve for Parameters Using the Point

Using the point \((0, 6)\): \[ 6 = a \cdot 2^{b \cdot 0} + 5 \] \[ 6 = a \cdot 1 + 5 \] \[ a = 1 \]

Step 6: Finalize the Equation

Since \( a = 1 \), the equation simplifies to: \[ y = 2^{bx} + 5 \]

Step 7: Determine the Value of \( b \)

To find \( b \), we need another point. However, since we only have one point, we assume \( b = 1 \) for simplicity, which fits the general shape of the graph.

Final Answer

\[ y = 2^x + 5 \]

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