Questions: The following data are the distances from the workplace (in miles) for the 12,14,20,7,2

The following data are the distances from the workplace (in miles) for the
12,14,20,7,2
Transcript text: The following data are the distances from the workplace (in miles) for the 12,14,20,7,2
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Solution

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Solution Steps

Step 1: Calculate the Mean

To find the mean \( \mu \) of the distances from the workplace, we use the formula:

\[ \mu = \frac{\sum_{i=1}^N x_i}{N} \]

where \( N \) is the number of data points and \( x_i \) are the individual distances. For our data:

\[ \mu = \frac{12 + 14 + 20 + 7 + 2}{5} = \frac{55}{5} = 11.0 \]

Thus, the mean of the distances is \( 11.0 \).

Step 2: Calculate the Variance

The variance \( \sigma^2 \) is calculated using the formula:

\[ \sigma^2 = \frac{\sum (x_i - \mu)^2}{N} \]

Substituting the values, we first find \( (x_i - \mu)^2 \) for each distance:

  • \( (12 - 11)^2 = 1 \)
  • \( (14 - 11)^2 = 9 \)
  • \( (20 - 11)^2 = 81 \)
  • \( (7 - 11)^2 = 16 \)
  • \( (2 - 11)^2 = 81 \)

Now, summing these values:

\[ \sum (x_i - \mu)^2 = 1 + 9 + 81 + 16 + 81 = 188 \]

Now, we calculate the variance:

\[ \sigma^2 = \frac{188}{5} = 37.6 \]

Step 3: Calculate the Standard Deviation

The standard deviation \( \sigma \) is the square root of the variance:

\[ \sigma = \sqrt{\sigma^2} = \sqrt{37.6} \approx 6.13 \]

Final Answer

The results are summarized as follows:

  • Mean \( \mu = 11.0 \)
  • Variance \( \sigma^2 = 37.6 \)
  • Standard Deviation \( \sigma \approx 6.13 \)

Thus, the final answers are:

\[ \boxed{\mu = 11.0} \] \[ \boxed{\sigma^2 = 37.6} \] \[ \boxed{\sigma \approx 6.13} \]

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