Questions: Use factoring to solve the quadratic equation. Check by solving x^2 - 4x - 21 = 0 The solution set is .

Use factoring to solve the quadratic equation. Check by solving

x^2 - 4x - 21 = 0

The solution set is .
Transcript text: Use factoring to solve the quadratic equation. Check by s \[ x^{2}-4 x-21=0 \] The solution set is $\square$ \}.
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Solution

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Solution Steps

To solve the quadratic equation \(x^2 - 4x - 21 = 0\) by factoring, we need to find two numbers that multiply to -21 and add up to -4. Once we find these numbers, we can factor the quadratic equation and solve for \(x\). Finally, we can check our solutions by substituting them back into the original equation.

Step 1: Write the Quadratic Equation

We start with the quadratic equation: \[ x^2 - 4x - 21 = 0 \]

Step 2: Factor the Quadratic Equation

We need to factor the quadratic equation. We look for two numbers that multiply to \(-21\) and add up to \(-4\). These numbers are \(-7\) and \(3\). Thus, we can factor the equation as: \[ (x - 7)(x + 3) = 0 \]

Step 3: Solve for \(x\)

To find the solutions, we set each factor equal to zero and solve for \(x\): \[ x - 7 = 0 \quad \Rightarrow \quad x = 7 \] \[ x + 3 = 0 \quad \Rightarrow \quad x = -3 \]

Step 4: Verify the Solutions

We substitute \(x = 7\) and \(x = -3\) back into the original equation to verify: For \(x = 7\): \[ 7^2 - 4(7) - 21 = 49 - 28 - 21 = 0 \] For \(x = -3\): \[ (-3)^2 - 4(-3) - 21 = 9 + 12 - 21 = 0 \] Both solutions satisfy the original equation.

Final Answer

\[ \boxed{x = 7, -3} \]

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