Questions: Use factoring to solve the quadratic equation. Check by solving
x^2 - 4x - 21 = 0
The solution set is .
Transcript text: Use factoring to solve the quadratic equation. Check by s
\[
x^{2}-4 x-21=0
\]
The solution set is $\square$ \}.
Solution
Solution Steps
To solve the quadratic equation \(x^2 - 4x - 21 = 0\) by factoring, we need to find two numbers that multiply to -21 and add up to -4. Once we find these numbers, we can factor the quadratic equation and solve for \(x\). Finally, we can check our solutions by substituting them back into the original equation.
Step 1: Write the Quadratic Equation
We start with the quadratic equation:
\[
x^2 - 4x - 21 = 0
\]
Step 2: Factor the Quadratic Equation
We need to factor the quadratic equation. We look for two numbers that multiply to \(-21\) and add up to \(-4\). These numbers are \(-7\) and \(3\). Thus, we can factor the equation as:
\[
(x - 7)(x + 3) = 0
\]
Step 3: Solve for \(x\)
To find the solutions, we set each factor equal to zero and solve for \(x\):
\[
x - 7 = 0 \quad \Rightarrow \quad x = 7
\]
\[
x + 3 = 0 \quad \Rightarrow \quad x = -3
\]
Step 4: Verify the Solutions
We substitute \(x = 7\) and \(x = -3\) back into the original equation to verify:
For \(x = 7\):
\[
7^2 - 4(7) - 21 = 49 - 28 - 21 = 0
\]
For \(x = -3\):
\[
(-3)^2 - 4(-3) - 21 = 9 + 12 - 21 = 0
\]
Both solutions satisfy the original equation.