Questions: Use the following function rule to find (f(0)). (f(x)=4^x+1) (f(0)=)

Use the following function rule to find (f(0)).

(f(x)=4^x+1)

(f(0)=)
Transcript text: Use the following function rule to find $f(0)$. \[ f(x)=4^{x}+1 \] $f(0)=$ Submit
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Solution

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Solution Steps

To find \( f(0) \) using the given function rule \( f(x) = 4^x + 1 \), substitute \( x = 0 \) into the function. This will allow us to calculate the value of the function at \( x = 0 \).

Step 1: Substitute \( x = 0 \) into the function

We start with the function defined as \( f(x) = 4^x + 1 \). To find \( f(0) \), we substitute \( x = 0 \): \[ f(0) = 4^0 + 1 \]

Step 2: Calculate \( 4^0 \)

Using the property of exponents, we know that \( 4^0 = 1 \). Therefore, we can simplify the expression: \[ f(0) = 1 + 1 \]

Step 3: Final Calculation

Now, we perform the final addition: \[ f(0) = 2 \]

Final Answer

The value of \( f(0) \) is \( \boxed{2} \).

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