Given \(f(x)\), substitute \(x = -2\) into \(f(x)\) to get \(f(-2) = 2\).
Similarly, for \(g(x)\), substitute \(x = -2\) into \(g(x)\) to get \(g(-2) = -2\).
The sum of \(f(x)\) and \(g(x)\) evaluated at \(x = -2\) is \(f(-2) + g(-2) = 2 - 2 = 0\).
\((f+g)(-2) = 0\)
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