Questions: Find the periodic withdrawals PMT for the given annuity account. (Assume end-of-period withdrawals and compounding at the same intervals as withdrawals. Round your answer to the nearest cent.)
200,000 at 2%, paid out quarterly for 19 years
PMT =
Transcript text: Find the periodic withdrawals PMT for the given annuity account. (Assume end-of-period withdrawals and compounding at the same intervals as withdrawals. Round your answer to the nearest cent.)
$200,000 at 2%, paid out quarterly for 19 years
PMT $=\$$
Solution
Solution Steps
To find the periodic withdrawals (PMT) for an annuity, we can use the formula for the present value of an annuity. The formula is:
\( PV \) is the present value of the annuity ($200,000 in this case).
\( r \) is the interest rate per period (annual rate divided by the number of periods per year).
\( n \) is the total number of periods (years multiplied by the number of periods per year).
\( PMT \) is the periodic payment we need to find.
Rearrange the formula to solve for PMT:
\[ PMT = PV \times \frac{r}{1 - (1 + r)^{-n}} \]
Step 1: Given Values
We are given the following values for the annuity:
Present Value (\( PV \)) = \$200,000
Annual Interest Rate = \( 0.02 \)
Compounding Periods per Year = \( 4 \) (quarterly)
Duration in Years = \( 19 \)
Step 2: Calculate Interest Rate per Period and Total Number of Periods
The interest rate per period (\( r \)) is calculated as:
\[
r = \frac{0.02}{4} = 0.005
\]
The total number of periods (\( n \)) is:
\[
n = 19 \times 4 = 76
\]
Step 3: Calculate Periodic Payment (PMT)
Using the formula for the periodic payment:
\[
PMT = PV \times \frac{r}{1 - (1 + r)^{-n}}
\]
Substituting the known values:
\[
PMT = 200000 \times \frac{0.005}{1 - (1 + 0.005)^{-76}}
\]
Calculating this gives:
\[
PMT \approx 3169.66
\]
Final Answer
The periodic withdrawals (\( PMT \)) for the annuity account are approximately \\(\boxed{3169.66}\\).