The equation \(\log_{3} 729 = n\) can be rewritten in its exponential form: \[ 3^n = 729 \]
We know that \(729\) is a power of \(3\). Let's find the exponent: \[ 3^6 = 729 \]
Since \(3^n = 3^6\), the exponents must be equal: \[ n = 6 \]
\(\boxed{n = 6}\)
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