Questions: A piece of sodium metal is submerged in mineral oil for storage. The sodium displaces 10.7 cubic centimeters of mineral oil. If the density of sodium metal is 0.972 g / cm^3, what is the mass in grams of the submerged piece?

A piece of sodium metal is submerged in mineral oil for storage. The sodium displaces 10.7 cubic centimeters of mineral oil. If the density of sodium metal is 0.972 g / cm^3, what is the mass in grams of the submerged piece?
Transcript text: Lecture_02-ST.pptx: CHEM Question 28 of 50 A piece of sodium metal is submerged in mineral oil for storage. The sodium displaces 10.7 cubic centimeters of mineral oil. If the density of sodium metal is $0.972 \mathrm{~g} / \mathrm{cm}^{3}$, what is the mass in grams of the submerged piece?
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Solution

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Solution Steps

Step 1: Identify the Given Values

We are given:

  • Volume of sodium metal, \( V = 10.7 \, \text{cm}^3 \)
  • Density of sodium metal, \( \rho = 0.972 \, \text{g/cm}^3 \)
Step 2: Use the Density Formula

The formula to find mass using density and volume is: \[ \text{mass} = \text{density} \times \text{volume} \]

Step 3: Substitute the Given Values

Substitute the given values into the formula: \[ \text{mass} = 0.972 \, \text{g/cm}^3 \times 10.7 \, \text{cm}^3 \]

Step 4: Calculate the Mass

Perform the multiplication: \[ \text{mass} = 0.972 \times 10.7 = 10.4004 \, \text{g} \]

Step 5: Round to Four Significant Digits

Round the result to four significant digits: \[ \text{mass} = 10.40 \, \text{g} \]

Final Answer

\[ \boxed{10.40 \, \text{g}} \]

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