Questions: For the given equation, solve the following:
x=-3(y+5)^2-8
Part 1 out of 3 Find the x - and y-intercepts (if they exist) and the vertex of the parabola. Enter the intercepts as a comma-separated list of points, if necessary. If an intercept does not exist, enter DNE in the appropriate field.
The x-intercept(s) are
The y-intercept(s) are
The vertex is
Transcript text: For the given equation, solve the following:
\[
x=-3(y+5)^{2}-8
\]
Part 1 out of 3
Find the $x$ - and $y$-intercepts (if they exist) and the vertex of the parabola. Enter the intercepts as a comma-separated list of points, if necessary. If an intercept does not exist, enter DNE in the appropriate field.
The $x$-intercept(s) are $\square$
The $y$-intercept(s) are $\square$
The vertex is $\square$
Solution
Solution Steps
To find the intercepts and the vertex of the given parabola, we can follow these steps:
Y-intercept: Set \( y = 0 \) in the equation and solve for \( x \).
X-intercept: Set \( x = 0 \) in the equation and solve for \( y \). If the solution is not real, the x-intercept does not exist.
Vertex: The vertex form of a parabola is \( x = a(y - k)^2 + h \). In this equation, the vertex is at \( (h, k) \). Rewrite the equation to identify \( h \) and \( k \).
Step 1: Finding the Y-Intercept
To find the \( y \)-intercept, we set \( y = 0 \) in the equation \( x = -3(y + 5)^2 - 8 \):