Questions: A glass of skim mik supplies 0.1 mg of iron and 8.3 g of protein. A quarter pound of lean meat provides 3.4 mg of iron and 23 g of protein. A person on a special diet is to have 10.7 mg of iror 110.5 g of protein. How many glasses of skim milk and how many quarter-pound servings of meat will provide this? How many glass(es) of skim milk and how many quarter-pound serving(s) of lean meat would be required?

Solution Steps

To solve this problem, we need to set up a system of linear equations based on the nutritional content of skim milk and lean meat. Let \( x \) be the number of glasses of skim milk and \( y \) be the number of quarter-pound servings of lean meat. We have two equations: one for iron and one for protein. Solve this system of equations to find the values of \( x \) and \( y \).

We define the variables:

• Let \( x \) be the number of glasses of skim milk.
• Let \( y \) be the number of quarter-pound servings of lean meat.

Based on the nutritional content, we can set up the following equations:

1. For iron: \[ 0.1x + 3.4y = 10.7 \]
2. For protein: \[ 8.3x + 23y = 110.5 \]

By solving the system of equations, we find:

• \( x = 5 \)
• \( y = 3 \)

Final Answer