Questions: Where: [OH^-] = hydroxide ion concentration (a) Use the rules for logarithms and exponents to solve for pOH in terms of [OH^-]. pOH =

Transcript text: Where: \[ \left[\mathrm{OH}^{-}\right]=\text {hydroxide ion concentration } \] (a) Use the rules for logarithms and exponents to solve for pOH in terms of $\left[\mathrm{OH}^{-}\right]$. NOTE: Capitalization counts. \[ \mathrm{pOH}= \] $\square$ Submit

Solution

Solution Steps

Step 1: Understanding the Relationship Between pOH and Hydroxide Ion Concentration

The pOH of a solution is defined as the negative logarithm (base 10) of the hydroxide ion concentration. This relationship can be expressed mathematically as: \[ \mathrm{pOH} = -\log_{10} \left[\mathrm{OH}^{-}\right] \]

Step 2: Applying the Logarithm Rule

To solve for pOH in terms of $\left[\mathrm{OH}^{-}\right]$, we use the definition directly. The logarithm rule states that the pOH is the negative logarithm of the hydroxide ion concentration.