Questions: Find the inverse of the given matrix, if it exists.
M=[
4 4
1 3
]
Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice.
A.
M^(-1)=[ ] (Simplify your answer. Type an integer or a fraction.)
B. The inverse matrix does not exist.
Transcript text: Find the inverse of the given matrix, if it exists.
\[
M=\left[\begin{array}{ll}
4 & 4 \\
1 & 3
\end{array}\right]
\]
Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice.
A. $\square$
$\square$ $\mathrm{M}^{-1}=\left[\begin{array}{c}\square \\ \square \\ \square\end{array}\right]$ (Simplify your answer. Type an integer or a fraction.)
$\square$
$\square$
B. The inverse matrix does not exist.
Solution
Solution Steps
To find the inverse of a given 2x2 matrix, we can use the formula for the inverse of a 2x2 matrix. The matrix \( M \) is given by:
\[
M=\left[\begin{array}{ll}
4 & 4 \\
1 & 3
\end{array}\right]
\]
The inverse of a 2x2 matrix \( \left[\begin{array}{ll}
a & b \\
c & d
\end{array}\right] \) is given by:
\[
M^{-1} = \frac{1}{ad - bc} \left[\begin{array}{ll}
d & -b \\
-c & a
\end{array}\right]
\]
First, we need to calculate the determinant \( ad - bc \). If the determinant is non-zero, we can then use the formula to find the inverse.
Solution Approach
Calculate the determinant of the matrix \( M \).
If the determinant is non-zero, use the formula to find the inverse matrix.
If the determinant is zero, the inverse does not exist.
Step 1: Calculate the Determinant
To find the inverse of the matrix \( M = \left[\begin{array}{ll} 4 & 4 \\ 1 & 3 \end{array}\right] \), we first calculate the determinant using the formula:
\[
\text{det}(M) = ad - bc = (4)(3) - (4)(1) = 12 - 4 = 8
\]
Thus, the determinant is \( \text{det}(M) = 8 \).
Step 2: Check the Determinant
Since the determinant \( \text{det}(M) \) is non-zero (\( 8 \neq 0 \)), the inverse of the matrix exists.
Step 3: Calculate the Inverse
Using the formula for the inverse of a 2x2 matrix:
\[
M^{-1} = \frac{1}{\text{det}(M)} \left[\begin{array}{ll} d & -b \\ -c & a \end{array}\right]
\]
we substitute \( a = 4 \), \( b = 4 \), \( c = 1 \), and \( d = 3 \):
\[
M^{-1} = \frac{1}{8} \left[\begin{array}{ll} 3 & -4 \\ -1 & 4 \end{array}\right] = \left[\begin{array}{ll} \frac{3}{8} & -\frac{1}{2} \\ -\frac{1}{8} & \frac{1}{2} \end{array}\right]
\]
Final Answer
The inverse matrix is:
\[
\boxed{M^{-1} = \left[\begin{array}{ll} \frac{3}{8} & -\frac{1}{2} \\ -\frac{1}{8} & \frac{1}{2} \end{array}\right]}
\]