Questions: H2CO3 + Ba(OH)2 → BaCO3 + H2O

Transcript text: $\square$ $\mathrm{H}_{2} \mathrm{CO}_{3}+$ $\square$ $\mathrm{Ba}(\mathrm{OH})_{2} \rightarrow$ $\square$ $\mathrm{BaCO}_{3}$ $+\square \mathrm{H}_{2} \mathrm{O}$

Solution

Solution Steps

Step 1: Identify the Chemical Reaction

The given chemical equation is a reaction between carbonic acid ($\mathrm{H}_2\mathrm{CO}_3$) and barium hydroxide ($\mathrm{Ba}(\mathrm{OH})_2$) to form barium carbonate ($\mathrm{BaCO}_3$) and water ($\mathrm{H}_2\mathrm{O}$).

Step 2: Write the Unbalanced Equation

The unbalanced chemical equation is:

\[ \square \, \mathrm{H}_2\mathrm{CO}_3 + \square \, \mathrm{Ba}(\mathrm{OH})_2 \rightarrow \square \, \mathrm{BaCO}_3 + \square \, \mathrm{H}_2\mathrm{O} \]

Step 3: Balance the Equation

Balance Barium (Ba):
There is 1 barium atom on both sides of the equation, so barium is already balanced.
Balance Carbon (C):
There is 1 carbon atom on both sides of the equation, so carbon is already balanced.
Balance Oxygen (O):
On the left side, there are 3 oxygen atoms from $\mathrm{H}_2\mathrm{CO}_3$ and 2 oxygen atoms from $\mathrm{Ba}(\mathrm{OH})_2$, totaling 5 oxygen atoms.
On the right side, there are 3 oxygen atoms in $\mathrm{BaCO}_3$ and 1 oxygen atom in each $\mathrm{H}_2\mathrm{O}$. To balance, we need 2 $\mathrm{H}_2\mathrm{O}$ molecules, giving a total of 5 oxygen atoms.
Balance Hydrogen (H):
On the left side, there are 2 hydrogen atoms from $\mathrm{H}_2\mathrm{CO}_3$ and 2 hydrogen atoms from $\mathrm{Ba}(\mathrm{OH})_2$, totaling 4 hydrogen atoms.
On the right side, with 2 $\mathrm{H}_2\mathrm{O}$ molecules, there are 4 hydrogen atoms.