Questions: Determine the value for c so that the limit as x approaches 4 of f(x) exists.
f(x) =
(1/4) x + c, for x < 4
-x + 7, for x > 4
The value of c is.
Transcript text: Determine the value for $c$ so that $\lim _{x \rightarrow 4} f(x)$ exists.
\[
f(x)=\left\{\begin{array}{ll}
\frac{1}{4} x+c, & \text { for } x<4 \\
-x+7, & \text { for } x>4
\end{array}\right.
\]
The value of $c$ is $\square$
Solution
Solution Steps
Step 1: Understand the problem
We are given a piecewise function \( f(x) \) defined as:
\[
f(x)=\left\{\begin{array}{ll}
\frac{1}{4} x+c, & \text { for } x<4 \\
-x+7, & \text { for } x>4
\end{array}\right.
\]
We need to determine the value of \( c \) such that the limit \( \lim _{x \rightarrow 4} f(x) \) exists.
Step 2: Determine the left-hand limit
The left-hand limit as \( x \) approaches 4 is given by the expression for \( x < 4 \):
\[
\lim_{x \rightarrow 4^-} f(x) = \frac{1}{4} \cdot 4 + c = 1 + c.
\]
Step 3: Determine the right-hand limit
The right-hand limit as \( x \) approaches 4 is given by the expression for \( x > 4 \):
\[
\lim_{x \rightarrow 4^+} f(x) = -4 + 7 = 3.
\]
Step 4: Set the left-hand limit equal to the right-hand limit
For the limit \( \lim_{x \rightarrow 4} f(x) \) to exist, the left-hand limit and the right-hand limit must be equal:
\[
1 + c = 3.
\]
Step 5: Solve for \( c \)
Solving the equation \( 1 + c = 3 \) gives:
\[
c = 3 - 1 = 2.
\]