Questions: 255.3 m / 87.63 s =□ m/s 405.29 g / 0.39 mL =□ g/mL 7.8084 cm × 0.6 cm =□ cm^2

255.3 m / 87.63 s =□ m/s 405.29 g / 0.39 mL =□ g/mL 7.8084 cm × 0.6 cm =□ cm^2
Transcript text: 255.3 m / 87.63 s =□ m/s 405.29 g / 0.39 mL =□ g/mL 7.8084 cm × 0.6 cm =□ cm^2
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Solution

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Solution Steps

Step 1: Division of Measurements for Velocity
  • Identify the given values: \( 255.3 \, \text{m} \) and \( 87.63 \, \text{s} \).
  • Perform the division: \( \frac{255.3}{87.63} \).
  • Determine the number of significant digits: The number with the fewest significant digits is \( 255.3 \) with 4 significant digits.
  • Calculate the result and round to 4 significant digits.
Step 2: Division of Measurements for Density
  • Identify the given values: \( 405.29 \, \text{g} \) and \( 0.39 \, \text{mL} \).
  • Perform the division: \( \frac{405.29}{0.39} \).
  • Determine the number of significant digits: The number with the fewest significant digits is \( 0.39 \) with 2 significant digits.
  • Calculate the result and round to 2 significant digits.
Step 3: Multiplication of Measurements for Area
  • Identify the given values: \( 7.8084 \, \text{cm} \) and \( 0.6 \, \text{cm} \).
  • Perform the multiplication: \( 7.8084 \times 0.6 \).
  • Determine the number of significant digits: The number with the fewest significant digits is \( 0.6 \) with 1 significant digit.
  • Calculate the result and round to 1 significant digit.

Final Answer

\[ \begin{aligned} 255.3 \mathrm{~m} \div 87.63 \mathrm{~s} & = \boxed{2.91 \frac{\mathrm{m}}{\mathrm{s}}} \\ 405.29 \mathrm{~g} \div 0.39 \mathrm{~mL} & = \boxed{1.0 \times 10^{3} \frac{\mathrm{g}}{\mathrm{mL}}} \\ 7.8084 \mathrm{~cm} \times 0.6 \mathrm{~cm} & = \boxed{5 \mathrm{~cm}^{2}} \end{aligned} \]

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