Find \(x\) and \(y\).
Find \(x\)
We have a right triangle with hypotenuse 6 and angle 60°. Using cosine, we have
\(\cos(60^\circ) = \frac{x}{6}\).
Since \(\cos(60^\circ) = \frac{1}{2}\), we have
\(x = 6 \cos(60^\circ) = 6(\frac{1}{2}) = 3\).
Find \(y\)
Using sine, we have
\(\sin(60^\circ) = \frac{y}{6}\).
Since \(\sin(60^\circ) = \frac{\sqrt{3}}{2}\), we have
\(y = 6 \sin(60^\circ) = 6(\frac{\sqrt{3}}{2}) = 3\sqrt{3}\).