Transcript text: Solve for $x$.
\[
\ln 2+\ln (x+1)=-3
\]
Solution
Solution Steps
To solve the equation \(\ln 2 + \ln (x+1) = -3\), we can use the properties of logarithms to combine the logarithmic terms and then exponentiate both sides to solve for \(x\).
Use the property of logarithms: \(\ln a + \ln b = \ln (a \cdot b)\).
Combine the logarithmic terms: \(\ln (2(x+1)) = -3\).
Exponentiate both sides to remove the natural logarithm: \(2(x+1) = e^{-3}\).
Solve for \(x\).
Step 1: Combine Logarithmic Terms
Given the equation:
\[
\ln 2 + \ln (x+1) = -3
\]
we use the property of logarithms \(\ln a + \ln b = \ln (a \cdot b)\) to combine the terms:
\[
\ln (2(x+1)) = -3
\]
Step 2: Exponentiate Both Sides
Exponentiate both sides to remove the natural logarithm:
\[
2(x+1) = e^{-3}
\]
Given \(e^{-3} \approx 0.04979\), we have:
\[
2(x+1) = 0.04979
\]
Step 3: Solve for \(x\)
Divide both sides by 2:
\[
x+1 = \frac{0.04979}{2}
\]
\[
x+1 \approx 0.02489
\]
Subtract 1 from both sides:
\[
x \approx 0.02489 - 1
\]
\[
x \approx -0.9751
\]
Step 4: Round to the Nearest Hundredth
Round the answer to the nearest hundredth:
\[
x \approx -0.98
\]