Given the parameters (n=5, p=5, q=1, k=0), it is advantageous to guess as the expected value is 0.2.
To calculate the expected value of guessing, we use the formula:
\[ EV = \frac{p}{n-k} - \frac{q \cdot (n-k-1)}{n-k} \]
Where,
- \(p = 5\) points are awarded for each correct answer,
- \(q = 1\) points are subtracted for each incorrect answer,
- \(n = 5\) is the total number of possible answers, and
- \(k = 1\) is the number of choices the examinee can eliminate as incorrect.
Substituting the given values into the formula, we get:
\[ EV = \frac{5}{5-1} - \frac{1 \cdot (5-1-1)}{5-1} = 0.5 \]
Since \(EV > 0\), it is to the examinee's advantage to guess. The expected value of guessing is positive, indicating an average gain in points.
Given the parameters (n=5, p=5, q=1, k=1), it is advantageous to guess as the expected value is 0.5.