Questions: Find the real solutions, if any, of the equation. Use the quadratic formula.
x^2+7x+7=0
Transcript text: Find the real solutions, if any, of the equation. Use the quadratic formula.
\[
x^{2}+7 x+7=0
\]
Solution
Solution Steps
Step 1: Identify the coefficients
The coefficients are \(a = 1\), \(b = 7\), and \(c = 7\).
Step 2: Calculate the discriminant
The discriminant, \(b^2 - 4ac\), is calculated as \(b^2 - 4 \cdot 1 \cdot 7 = 21\).
Step 3: Determine the nature of the roots
Since the discriminant is greater than 0, the equation has two distinct real roots.
Step 4: Calculate the roots using the quadratic formula
The roots are calculated using the formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).
Substituting the values, we get \(x_1 = (-1.21+0j)\) and \(x_2 = (-5.79+0j)\).
Final Answer:
The roots of the equation \(ax^2 + bx + c = 0\) are \(x_1 = (-1.21+0j)\) and \(x_2 = (-5.79+0j)\).