The graph shows that the concentration of B levels off at approximately 0.12 M.
The graph shows that the concentration of A levels off at approximately 0.54 M.
The balanced reaction is 2A(g) ⇌ B(g). Therefore, the equilibrium expression is: \(K_c = \frac{[B]}{[A]^2}\)
Substitute the equilibrium concentrations into the equilibrium expression: \(K_c = \frac{0.12}{(0.54)^2}\) \(K_c = \frac{0.12}{0.2916}\) \(K_c \approx 0.41\)
\\(\boxed{K_c = 0.41}\\)
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