Questions: Intervalos de clase Marca de clase Frecuencia Frecuencia Relativa Frecuencia Relativa acumulada 7,5 137,3 72,4 11 0,22 22 137,3 267,1 202,2 13 0,26 48 267,1 396,9 332 12 0,24 72 396,9 526,7 461,8 6 0,12 84 526,7 656,5 591,6 8 0,16 100

Intervalos de clase  Marca de clase  Frecuencia  Frecuencia Relativa  Frecuencia Relativa acumulada
7,5  137,3  72,4  11  0,22  22
137,3  267,1  202,2  13  0,26  48
267,1  396,9  332  12  0,24  72
396,9  526,7  461,8  6  0,12  84
526,7  656,5  591,6  8  0,16  100
Transcript text: \begin{tabular}{|c|c|c|c|c|c|} \hline \multicolumn{2}{|c|}{ Intervalos de clase } & Marca de clase & Frecuencia & Frecuencia Relativa & Frecuencia Relativa acumulada \\ \hline 7,5 & 137,3 & 72,4 & 11 & 0,22 & 22 \\ \hline 137,3 & 267,1 & 202,2 & 13 & 0,26 & 48 \\ \hline 267,1 & 396,9 & 332 & 12 & 0,24 & 72 \\ \hline 396,9 & 526,7 & 461,8 & 6 & 0,12 & 84 \\ \hline 526,7 & 656,5 & 591,6 & 8 & 0,16 & 100 \\ \hline \end{tabular}
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Solution

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Solution Steps

Step 1: Calculate the Total Frequency

Sum the frequencies to get the total frequency. \[ 11 + 13 + 12 + 6 + 8 = 50 \]

Step 2: Calculate the Relative Frequencies

Divide each frequency by the total frequency to get the relative frequencies. \[ \text{Relative Frequency} = \frac{\text{Frequency}}{\text{Total Frequency}} \]

  • For 11: \(\frac{11}{50} = 0.22\)
  • For 13: \(\frac{13}{50} = 0.26\)
  • For 12: \(\frac{12}{50} = 0.24\)
  • For 6: \(\frac{6}{50} = 0.12\)
  • For 8: \(\frac{8}{50} = 0.16\)
Step 3: Calculate the Cumulative Relative Frequencies

Add the relative frequencies sequentially to get the cumulative relative frequencies.

  • First interval: \(0.22\)
  • Second interval: \(0.22 + 0.26 = 0.48\)
  • Third interval: \(0.48 + 0.24 = 0.72\)
  • Fourth interval: \(0.72 + 0.12 = 0.84\)
  • Fifth interval: \(0.84 + 0.16 = 1.00\)

Final Answer

The table is already correctly filled with the calculated values. The steps confirm the accuracy of the given data.

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