Questions: How many moles of Ag are in 47.6 grams of Ag2O?

Solution Steps

First, we need to calculate the molar mass of silver oxide ($\mathrm{Ag}_{2} \mathrm{O}$). The molar masses of the elements involved are:

• Silver (Ag): 107.87 g/mol
• Oxygen (O): 16.00 g/mol

The molar mass of $\mathrm{Ag}_{2} \mathrm{O}$ is: $$2 \times 107.87 \, \text{g/mol} + 16.00 \, \text{g/mol} = 231.74 \, \text{g/mol}$$

Next, we use the given mass of $\mathrm{Ag}_{2} \mathrm{O}$ to find the number of moles. The formula to convert grams to moles is: $$\text{moles} = \frac{\text{mass}}{\text{molar mass}}$$

Given mass of $\mathrm{Ag}_{2} \mathrm{O}$ is 47.6 grams: $$\text{moles of } \mathrm{Ag}_{2} \mathrm{O} = \frac{47.6 \, \text{g}}{231.74 \, \text{g/mol}} = 0.2054 \, \text{moles}$$

Since each molecule of $\mathrm{Ag}_{2} \mathrm{O}$ contains 2 atoms of Ag, the number of moles of Ag is twice the number of moles of $\mathrm{Ag}_{2} \mathrm{O}$: $$\text{moles of Ag} = 2 \times 0.2054 = 0.4108 \, \text{moles}$$

Final Answer