Questions: Consider the function f(x)=x^2-5x if x<3 7x-4 if x≥3. Evaluate lim x→3+ f(x) and lim x→3+ f(x). a.) lim x→3− f(x)=-6 lim x→3+ f(x)=-6 b.) lim x→3− f(x)=-6 lim x→3+ f(x)=17 c.) lim x→3− f(x)=17 lim x→3+ f(x)=17 d.) lim x→3− f(x)=17 lim x→3+ f(x)=-6

Consider the function f(x)=x^2-5x if x<3 7x-4 if x≥3. Evaluate lim x→3+ f(x) and lim x→3+ f(x).
a.) lim x→3− f(x)=-6 lim x→3+ f(x)=-6
b.)
lim x→3− f(x)=-6 lim x→3+ f(x)=17
c.)
lim x→3− f(x)=17 lim x→3+ f(x)=17
d.)
lim x→3− f(x)=17 lim x→3+ f(x)=-6
Transcript text: Consider the function $f(x)=\left\{\begin{array}{ll}x^{2}-5 x & \text { if } x<3 \\ 7 x-4 & \text { if } x \geq 3\end{array}\right.$. Evaluate $\lim _{x \rightarrow 3^{+}} f(x)$ and $\lim _{x \rightarrow 3^{+}} f(x)$. a.) $\lim _{x \rightarrow 3^{-}} f(x)=-6$ $\lim _{x \rightarrow 3^{+}} f(x)=-6$ b.) \[ \begin{array}{l} \lim _{x \rightarrow 3^{-}} f(x)=-6 \\ \lim _{x \rightarrow 3^{+}} f(x)=17 \end{array} \] c.) \[ \begin{array}{l} \lim _{x \rightarrow 3^{-}} f(x)=17 \\ \lim _{x \rightarrow 3^{+}} f(x)=17 \end{array} \] d.) \[ \begin{array}{l} \lim _{x \rightarrow 3^{-}} f(x)=17 \\ \lim _{x \rightarrow 3^{+}} f(x)=-6 \end{array} \]
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Solution

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Solution Steps

To evaluate the limits of the piecewise function \( f(x) \) as \( x \) approaches 3 from the left (\( x \rightarrow 3^{-} \)) and from the right (\( x \rightarrow 3^{+} \)), we need to consider the definition of the function for values less than 3 and for values greater than or equal to 3.

  1. For \( x < 3 \), the function is defined as \( f(x) = x^2 - 5x \).
  2. For \( x \geq 3 \), the function is defined as \( f(x) = 7x - 4 \).

We will evaluate the limits by substituting \( x = 3 \) into the respective parts of the function.

Step 1: Evaluate \( \lim_{x \rightarrow 3^{-}} f(x) \)

For \( x < 3 \), the function is defined as: \[ f(x) = x^2 - 5x \] To find the left-hand limit as \( x \) approaches 3, we substitute \( x = 3 \): \[ \lim_{x \rightarrow 3^{-}} f(x) = 3^2 - 5 \cdot 3 = 9 - 15 = -6 \]

Step 2: Evaluate \( \lim_{x \rightarrow 3^{+}} f(x) \)

For \( x \geq 3 \), the function is defined as: \[ f(x) = 7x - 4 \] To find the right-hand limit as \( x \) approaches 3, we substitute \( x = 3 \): \[ \lim_{x \rightarrow 3^{+}} f(x) = 7 \cdot 3 - 4 = 21 - 4 = 17 \]

Final Answer

The limits are: \[ \lim_{x \rightarrow 3^{-}} f(x) = -6 \] \[ \lim_{x \rightarrow 3^{+}} f(x) = 17 \] Thus, the final answer is: \[ \boxed{\text{a.) } \lim_{x \rightarrow 3^{-}} f(x) = -6, \lim_{x \rightarrow 3^{+}} f(x) = 17} \]

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