To solve the equation \(\frac{x-2}{15}-\frac{2}{5}=\frac{-2 x+3}{3}\), we need to find the value of \(x\). The approach involves:
Finding a common denominator for the fractions.
Simplifying the equation by eliminating the fractions.
Solving the resulting linear equation for \(x\).
Step 1: Set Up the Equation
We start with the given equation:
\[
\frac{x-2}{15} - \frac{2}{5} = \frac{-2x+3}{3}
\]
Step 2: Find a Common Denominator
To eliminate the fractions, we find a common denominator. The least common multiple of 15, 5, and 3 is 15. We rewrite each term with a denominator of 15:
\[
\frac{x-2}{15} - \frac{6}{15} = \frac{-10x + 15}{15}
\]
Step 3: Combine the Fractions
Combine the fractions on the left-hand side:
\[
\frac{x-2-6}{15} = \frac{-10x + 15}{15}
\]
Simplify the numerator:
\[
\frac{x-8}{15} = \frac{-10x + 15}{15}
\]
Step 4: Eliminate the Denominator
Since the denominators are the same, we can equate the numerators:
\[
x - 8 = -10x + 15
\]
Step 5: Solve for \(x\)
Rearrange the equation to isolate \(x\):
\[
x + 10x = 15 + 8
\]
\[
11x = 23
\]
\[
x = \frac{23}{11} \approx 2.0909
\]