Questions: 3.1.6 Quiz: Free Fall Question 1 of 10 A stuntman jumps from the roof of a building to the safety net below. How far has the stuntman fallen after 2.3 seconds? A. 25.9 m B. 9.8 m C. 11.3 m D. 21.2 m SUBMIT PREVIOUS

Solution Steps

In this problem, we are dealing with free fall, which means the only force acting on the stuntman is gravity. The acceleration due to gravity is $g = 9.8 \, \text{m/s}^2$. The time of fall is given as $t = 2.3 \, \text{s}$.

The formula to calculate the distance fallen under constant acceleration (gravity) is: $$d = \frac{1}{2} g t^2$$ where $d$ is the distance fallen, $g$ is the acceleration due to gravity, and $t$ is the time.

Substitute $g = 9.8 \, \text{m/s}^2$ and $t = 2.3 \, \text{s}$ into the formula: $$d = \frac{1}{2} \times 9.8 \times (2.3)^2$$

First, calculate $(2.3)^2$: $$(2.3)^2 = 5.29$$ Now, calculate the distance: $$d = \frac{1}{2} \times 9.8 \times 5.29 = 25.9461 \, \text{m}$$

Round the result to one decimal place to match the options provided: $$d \approx 25.9 \, \text{m}$$

Final Answer