Questions: A line has slope 3/4 and passes through the point (8,-3).
By substituting into the equation y=mx+b, find the value of b for this line.
Transcript text: 42. A line has slope $\frac{3}{4}$ and passes through the point $(8,-3)$.
42a By substituting into the equation $y=m x+b$, find the value of $b$ for this line.
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Solution
Solution Steps
Step 1: Identify the given information
We are given the slope \( m = \frac{3}{4} \) and a point on the line \( (8, -3) \).
Step 2: Substitute the given information into the slope-intercept form
The slope-intercept form of a line is given by:
\[ y = mx + b \]
Substitute \( m = \frac{3}{4} \), \( x = 8 \), and \( y = -3 \) into the equation:
\[ -3 = \frac{3}{4}(8) + b \]
Step 3: Solve for \( b \)
First, calculate \( \frac{3}{4} \times 8 \):
\[ \frac{3}{4} \times 8 = 6 \]
Now substitute back into the equation:
\[ -3 = 6 + b \]
Subtract 6 from both sides to solve for \( b \):
\[ b = -3 - 6 \]
\[ b = -9 \]