Questions: A line has slope 3/4 and passes through the point (8,-3). By substituting into the equation y=mx+b, find the value of b for this line.

A line has slope 3/4 and passes through the point (8,-3).

By substituting into the equation y=mx+b, find the value of b for this line.
Transcript text: 42. A line has slope $\frac{3}{4}$ and passes through the point $(8,-3)$. 42a By substituting into the equation $y=m x+b$, find the value of $b$ for this line. Enter your next step here
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Solution

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Solution Steps

Step 1: Identify the given information

We are given the slope m=34 m = \frac{3}{4} and a point on the line (8,3) (8, -3) .

Step 2: Substitute the given information into the slope-intercept form

The slope-intercept form of a line is given by: y=mx+b y = mx + b Substitute m=34 m = \frac{3}{4} , x=8 x = 8 , and y=3 y = -3 into the equation: 3=34(8)+b -3 = \frac{3}{4}(8) + b

Step 3: Solve for b b

First, calculate 34×8 \frac{3}{4} \times 8 : 34×8=6 \frac{3}{4} \times 8 = 6 Now substitute back into the equation: 3=6+b -3 = 6 + b Subtract 6 from both sides to solve for b b : b=36 b = -3 - 6 b=9 b = -9

Final Answer

b=9 \boxed{b = -9}

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