Questions: simplify the fraction
[
fracfrac13+x-frac13x
]
Transcript text: simplify the fraction
\[
\frac{\frac{1}{3+x}-\frac{1}{3}}{x}
\]
Solution
Solution Steps
To simplify the given fraction, we need to perform the following steps:
Find a common denominator for the fractions in the numerator.
Subtract the fractions in the numerator.
Simplify the resulting expression by dividing by \(x\).
Step 1: Find a Common Denominator
To simplify the expression \(\frac{\frac{1}{3+x} - \frac{1}{3}}{x}\), we first find a common denominator for the fractions in the numerator. The common denominator for \(\frac{1}{3+x}\) and \(\frac{1}{3}\) is \((3+x) \cdot 3\).
Step 2: Subtract the Fractions
Using the common denominator, we rewrite the fractions:
\[
\frac{1}{3+x} = \frac{3}{3(3+x)}
\]
\[
\frac{1}{3} = \frac{3+x}{3(3+x)}
\]
Subtracting these, we get:
\[
\frac{3 - (3+x)}{3(3+x)} = \frac{-x}{3(3+x)}
\]
Step 3: Simplify the Expression
Now, divide the result by \(x\):
\[
\frac{\frac{-x}{3(3+x)}}{x} = \frac{-x}{3x(3+x)}
\]
Simplifying further, we cancel \(x\) in the numerator and denominator:
\[
\frac{-1}{3(3+x)}
\]
Final Answer
The simplified expression is:
\[
\boxed{\frac{-1}{3(3+x)}}
\]