Questions: Answer the following questions about the function whose derivative is given below.
a. What are the critical points of f ?
b. On what open intervals is f increasing or decreasing?
c. At what points, if any, does f assume local maximum or minimum values?
f'(x)=(sqrt(3) sin x+cos x)(sin x-sqrt(3) cos x), 0 ≤ x ≤ 2 pi
a. What are the critical points of f ? Select the correct choice below and, if necessary, fill in the answer box to
A. The critical point(s) of f is/are x=
(Type an exact answer, using pi as needed. Use a comma to separate answers as needed.)
B. The function f has no critical points.
Transcript text: Answer the following questions about the function whose derivative is given below.
a. What are the critical points of $f$ ?
b. On what open intervals is $f$ increasing or decreasing?
c. At what points, if any, does f assume local maximum or minimum values?
\[
f^{\prime}(x)=(\sqrt{3} \sin x+\cos x)(\sin x-\sqrt{3} \cos x), 0 \leq x \leq 2 \pi
\]
a. What are the critical points of $f$ ? Select the correct choice below and, if necessary, fill in the answer box to
A. The critical point(s) of $f$ is/are $x=$ $\square$
(Type an exact answer, using $\pi$ as needed. Use a comma to separate answers as needed.)
B. The function $f$ has no critical points.
Solution
Solution Steps
To solve the given problem, we need to find the critical points of the function \( f \) whose derivative is given. Critical points occur where the derivative is zero or undefined. We will set the given derivative equal to zero and solve for \( x \) within the interval \( [0, 2\pi] \).
Solution Approach
Set the derivative \( f'(x) = (\sqrt{3} \sin x + \cos x)(\sin x - \sqrt{3} \cos x) \) equal to zero.
Solve the resulting equations \( \sqrt{3} \sin x + \cos x = 0 \) and \( \sin x - \sqrt{3} \cos x = 0 \) for \( x \) within the interval \( [0, 2\pi] \).
Combine the solutions to find all critical points.
Step 1: Finding Critical Points
To find the critical points of the function \( f \), we set the derivative \( f'(x) = (\sqrt{3} \sin x + \cos x)(\sin x - \sqrt{3} \cos x) \) equal to zero. Solving this equation, we find that the critical point occurs at:
\[
x \approx 1.0472
\]
Step 2: Expressing Critical Points
The critical point can be expressed in terms of radians. Notably, \( 1.0472 \) radians is equivalent to \( \frac{\pi}{3} \). Thus, the critical point is: