Questions: A blue-eyed, left-handed woman has children with a brown-eyed, right-handed man who is heterozygous for both of his traits. If blue eyes and left-handedness are recessive, how many different phenotypes are possible in their children? Multiple Choice four two one five

The answer is the first one: four.

Explanation:

1. Eye Color:

   • Blue eyes are recessive (bb).
   • Brown eyes are dominant (B), and the man is heterozygous (Bb).

2. Handedness:

   • Left-handedness is recessive (ll).
   • Right-handedness is dominant (R), and the man is heterozygous (Rr).

The woman has the genotype bbll (blue-eyed, left-handed), and the man has the genotype BbRr (brown-eyed, right-handed).

To determine the possible phenotypes of their children, we need to consider the combinations of these traits:

• Eye Color:

  • The children can inherit either B or b from the father and b from the mother.
  • Possible genotypes: Bb (brown eyes) or bb (blue eyes).

• Handedness:

  • The children can inherit either R or r from the father and l from the mother.
  • Possible genotypes: Rl (right-handed) or ll (left-handed).

Combining these, the possible phenotypes are:

1. Brown eyes, right-handed (BbRl)
2. Brown eyes, left-handed (Bbll)
3. Blue eyes, right-handed (bbRl)
4. Blue eyes, left-handed (bbll)

Thus, there are four different phenotypes possible in their children.