Questions: Wilbur is working in a lab testing bacteria populations. After starting out with a population of 394 bacteria, he observes the change in population and notices population triples every 25 minutes. Find the population after 2 hours. Round to the nearest bacterium.

Wilbur is working in a lab testing bacteria populations. After starting out with a population of 394 bacteria, he observes the change in population and notices population triples every 25 minutes.

Find the population after 2 hours. Round to the nearest bacterium.
Transcript text: Wilbur is working in a lab testing bacteria populations. After starting out with a population of 394 bacteria, he observes the change in population and notices population triples every 25 minutes. Find the population after 2 hours. Round to the nearest bacterium.
failed

Solution

failed
failed

To find the population of bacteria after 2 hours, given that the population triples every 25 minutes, we can use the formula for exponential growth:

P(t)=P0×r(t/T) P(t) = P_0 \times r^{(t/T)}

where:

  • P(t) P(t) is the population at time t t ,
  • P0 P_0 is the initial population,
  • r r is the growth factor (in this case, 3 since the population triples),
  • t t is the total time elapsed,
  • T T is the time it takes for the population to triple (25 minutes).

Given:

  • P0=394 P_0 = 394 bacteria,
  • r=3 r = 3 ,
  • t=2 t = 2 hours = 120 minutes,
  • T=25 T = 25 minutes.

Now, substitute these values into the formula:

P(120)=394×3(120/25) P(120) = 394 \times 3^{(120/25)}

First, calculate 120/25 120/25 :

120/25=4.8 120/25 = 4.8

Now, calculate 34.8 3^{4.8} :

34.8104.603 3^{4.8} \approx 104.603

Finally, calculate the population:

P(120)=394×104.60341236.782 P(120) = 394 \times 104.603 \approx 41236.782

Rounding to the nearest bacterium, the population after 2 hours is approximately:

41237 \boxed{41237} bacteria.

Was this solution helpful?
failed
Unhelpful
failed
Helpful