Questions: Use the given function to answer the questions that follow. f(x) = x^4 - 4x^2 a) Use the Leading Coefficient Test to determine the graph's end behavior. A. The graph of f(x) rises left and falls right. B. The graph of f(x) falls left and falls right. C. The graph of f(x) falls left and rises right. D. The graph of f(x) rises left and rises right. b) Find the x-intercepts. x = (Use a comma to separate answers as needed.)

Use the given function to answer the questions that follow.
f(x) = x^4 - 4x^2
a) Use the Leading Coefficient Test to determine the graph's end behavior.
A. The graph of f(x) rises left and falls right.
B. The graph of f(x) falls left and falls right.
C. The graph of f(x) falls left and rises right.
D. The graph of f(x) rises left and rises right.
b) Find the x-intercepts.
x = 
(Use a comma to separate answers as needed.)
Transcript text: Use the given function to answer the questions that follow. \[ f(x)=x^{4}-4 x^{2} \] a) Use the Leading Coefficient Test to determine the graph's end behavior. A. The graph of $f(x)$ rises left and falls right. B. The graph of $f(x)$ falls left and falls right. C. The graph of $f(x)$ falls left and rises right. D. The graph of $f(x)$ rises left and rises right. b) Find the $x$-intercepts. \[ \mathrm{x}=\square \] (Use a comma to separate answers as needed.)
failed

Solution

failed
failed

Solution Steps

Step 1: Determine the End Behavior

Using the Leading Coefficient Test, we analyze the function \( f(x) = x^4 - 4x^2 \). The leading term is \( x^4 \), which has a positive coefficient (1) and an even degree (4). Therefore, the end behavior of the graph is:

The graph of \( f(x) \) rises left and rises right.

Step 2: Factor the Polynomial

Next, we factor the polynomial \( f(x) = x^4 - 4x^2 \). The factorization yields:

\[ f(x) = x^2 (x - 2)(x + 2) \]

Step 3: Find the x-Intercepts

To find the x-intercepts, we set the factored expression equal to zero:

\[ x^2 = 0 \quad \Rightarrow \quad x = 0 \] \[ x - 2 = 0 \quad \Rightarrow \quad x = 2 \] \[ x + 2 = 0 \quad \Rightarrow \quad x = -2 \]

Thus, the x-intercepts are \( x = 0, 2, -2 \).

Final Answer

The end behavior of the graph is: \(\boxed{\text{The graph of } f(x) \text{ rises left and rises right.}}\)

The x-intercepts are: \(\boxed{x = 0, 2, -2}\)

Was this solution helpful?
failed
Unhelpful
failed
Helpful