Questions: chemical equation for lodine in cyclohexane + sodium chloride

chemical equation for lodine in cyclohexane + sodium chloride
Transcript text: chemical equation for lodine in cyclohexane + sodium chloride
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Solution

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Solution Steps

Step 1: Identify the Reactants

The reactants in this scenario are iodine (\( \text{I}_2 \)) dissolved in cyclohexane and sodium chloride (\( \text{NaCl} \)). Cyclohexane is a non-polar solvent, and iodine is a non-polar molecule, which means iodine will dissolve well in cyclohexane. Sodium chloride is an ionic compound.

Step 2: Consider Possible Reactions

In general, iodine in cyclohexane and sodium chloride do not react with each other. Iodine is a halogen and sodium chloride is a stable ionic compound. There is no driving force for a chemical reaction between these two substances under normal conditions.

Step 3: Write the Chemical Equation

Since there is no chemical reaction between iodine in cyclohexane and sodium chloride, the chemical equation simply represents the presence of these substances without any change:

\[ \text{I}_2 (\text{in cyclohexane}) + \text{NaCl} \rightarrow \text{No Reaction} \]

Final Answer

\[ \boxed{\text{No Reaction}} \]

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