Questions: Using a constant of variation of 6/7, complete the table of values for the relationship between x and y. Write your answers in the spaces provided. x 0 14 □ y 6 18 24

Using a constant of variation of 6/7, complete the table of values for the relationship between x and y.
Write your answers in the spaces provided.

x  0   14   □
y   6   18  24
Transcript text: \$ 8 Using a constant of variation of $\frac{6}{7}$, complete the table of values for the relationship between $x$ and $y$. Write your answers in the spaces provided. \begin{tabular}{|c|c|c|c|c|c|} \hline$x$ & 0 & & 14 & & $\square$ \\ \hline$y$ & & 6 & & 18 & 24 \\ \hline \end{tabular} Copying permitted for classroom use.
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Solution

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Solution Steps

To solve this problem, we need to use the concept of direct variation, where \( y = kx \) and \( k \) is the constant of variation. Given \( k = \frac{6}{7} \), we can find the missing values in the table by applying this formula. For each pair of \( x \) and \( y \), if one value is missing, we can solve for it using the equation \( y = \frac{6}{7}x \).

Step 1: Determine the Constant of Variation

The constant of variation is given as \( k = \frac{6}{7} \).

Step 2: Calculate Missing \( y \) Values

Using the formula \( y = kx \):

  • For \( x = 0 \): \[ y = \frac{6}{7} \cdot 0 = 0 \]
  • For \( x = 14 \): \[ y = \frac{6}{7} \cdot 14 = 12 \]
Step 3: Calculate Missing \( x \) Values

Using the formula \( x = \frac{y}{k} \):

  • For \( y = 6 \): \[ x = \frac{6}{\frac{6}{7}} = 7 \]
  • For \( y = 18 \): \[ x = \frac{18}{\frac{6}{7}} = 21 \]
  • For \( y = 24 \): \[ x = \frac{24}{\frac{6}{7}} = 28 \]

Final Answer

The completed table of values is: \[ \begin{array}{|c|c|} \hline x & y \\ \hline 0 & 0 \\ 7 & 6 \\ 14 & 12 \\ 21 & 18 \\ 28 & 24 \\ \hline \end{array} \] Thus, the final answers are: \[ \boxed{(x = 0, y = 0), (x = 7, y = 6), (x = 14, y = 12), (x = 21, y = 18), (x = 28, y = 24)} \]

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