Questions: (-3.4 × 10^4 μg/dL) · (10^-12 g/1 μ) × (1 dL/100 mL) F=? g/mL

Solution Steps

The problem provides a unit conversion equation that needs to be completed. The given part of the equation is:

\[ \left(-3.4 \times 10^{4} \frac{\mu \mathrm{~g}}{\mathrm{dL}}\right) \cdot\left(\frac{10^{-12} \mathrm{~g}}{1 \mu}\right) \times\left(\frac{1 \mathrm{dL}}{100 \mathrm{~mL}}\right) \mathrm{F}=? \frac{\mathrm{~g}}{\mathrm{~mL}} \]

We need to fill in the missing part of this equation to convert the units correctly.

The goal is to convert from \(\mu \mathrm{g/dL}\) to \(\mathrm{g/mL}\). The given conversion factors are:

1. \(\frac{10^{-12} \mathrm{~g}}{1 \mu}\) converts micrograms to grams.
2. \(\frac{1 \mathrm{dL}}{100 \mathrm{~mL}}\) converts deciliters to milliliters.

The missing part of the equation should ensure that all units cancel out correctly, leaving \(\mathrm{g/mL}\) as the final unit. The given conversion factors already handle the conversion from \(\mu \mathrm{g}\) to \(\mathrm{g}\) and from \(\mathrm{dL}\) to \(\mathrm{mL}\).

Since the given conversion factors already convert \(\mu \mathrm{g/dL}\) to \(\mathrm{g/mL}\), no additional conversion factor is needed. The equation is complete as it stands, and the missing part is simply the identity factor, which does not change the value.

Final Answer