Questions: Question 12 Simplify. Assume all variables are nonnegative. √(48 b^12 y^5 / b^5 y^15)=

Question 12
Simplify. Assume all variables are nonnegative.
√(48 b^12 y^5 / b^5 y^15)=
Transcript text: Question 12 Simplify. Assume all variables are nonnegative. \[ \sqrt{\frac{48 b^{12} y^{5}}{b^{5} y^{15}}}= \] $\square$
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Solution

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Solution Steps

To simplify the given expression, we will first simplify the fraction inside the square root by dividing the exponents of like bases. Then, we will take the square root of the resulting expression by applying the square root to both the coefficient and the variables separately.

Step 1: Simplifying the Expression

We start with the expression

\[ \sqrt{\frac{48 b^{12} y^{5}}{b^{5} y^{15}}} \]

First, we simplify the fraction inside the square root by dividing the coefficients and the variables separately.

Step 2: Simplifying the Coefficient

The coefficient \(48\) can be factored as \(16 \cdot 3\), and since \(16\) is a perfect square, we can take its square root:

\[ \sqrt{48} = \sqrt{16 \cdot 3} = 4\sqrt{3} \]

Step 3: Simplifying the Variables

Next, we simplify the variables:

\[ \frac{b^{12}}{b^{5}} = b^{12-5} = b^{7} \]

\[ \frac{y^{5}}{y^{15}} = y^{5-15} = y^{-10} = \frac{1}{y^{10}} \]

Combining these results, we have:

\[ \sqrt{\frac{48 b^{12} y^{5}}{b^{5} y^{15}}} = \sqrt{4\sqrt{3} \cdot b^{7} \cdot \frac{1}{y^{10}}} = 4\sqrt{3} \cdot \frac{b^{7/2}}{y^{5}} \]

Final Answer

Thus, the simplified expression is

\[ \boxed{4\sqrt{3} \cdot \frac{b^{7/2}}{y^{5}}} \]

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