Absorbance (\(A\)) and percent transmission (\(T\)) are related by the formula: \[ A = -\log_{10}\left(\frac{T}{100}\right) \]
Given the percent transmission \(T = 68.6\%\), we first convert it to a decimal: \[ \frac{T}{100} = \frac{68.6}{100} = 0.686 \]
Using the formula from Step 1, we substitute \(T = 0.686\): \[ A = -\log_{10}(0.686) \]
Calculate the logarithm: \[ \log_{10}(0.686) \approx -0.1635 \]
Finally, we find the absorbance: \[ A = -(-0.1635) = 0.1635 \]
\(\boxed{A = 0.1635}\)
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