La integral dada es: \[ \int \frac{2x}{x^{2}+1} \, dx \]
Sea \( u = x^{2} + 1 \). Entonces, la derivada de \( u \) con respecto a \( x \) es: \[ \frac{du}{dx} = 2x \quad \Rightarrow \quad du = 2x \, dx \]
Sustituyendo \( u \) y \( du \) en la integral original: \[ \int \frac{2x}{x^{2}+1} \, dx = \int \frac{1}{u} \, du \]
La integral de \( \frac{1}{u} \) con respecto a \( u \) es: \[ \int \frac{1}{u} \, du = \ln|u| + C \]
Sustituyendo \( u = x^{2} + 1 \) de nuevo en la expresión: \[ \ln|u| + C = \ln(x^{2} + 1) + C \]
La respuesta correcta es: \[ \boxed{\ln(x^{2} + 1) + C} \]
\(\boxed{\ln(x^{2} + 1) + C}\)
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