Questions: Lab Quiz Review
UNIVERSITY
- Practice Question
- Find the correct information for XeF2: # of electron groups, electron geometry, bond angle, # of bonded atoms, molecular geometry,
- A) 5, trigonal bipyramidal, 120 90, 2, linear
- B) 3, trigonal planar, 120, 2, bent
- C) 4, tetrahedral, 109.5, 2, bent
- D) 2, linear, 180, 2, linear
Transcript text: Lab Quiz Review
UNIVERSITY
- Practice Question
- Find the correct information for XeF2: # of electron groups, electron geometry, bond angle, # of bonded atoms, molecular geometry,
- A) 5 , trigonal bipyramidal, $120 \& 90,2$, linear
- B) 3 , trigonal planar, 120,2 , bent
- C) 4 , tetrahedral, $109.5,2$, bent
- D) 2 , linear, 180,2 , linear
Solution
Solution Steps
Step 1: Determine the Number of Electron Groups
To find the number of electron groups around the central atom in xenon difluoride (XeF\(_2\)), we need to consider both the bonded atoms and lone pairs on the central atom, xenon (Xe). Xenon has 8 valence electrons. In XeF\(_2\), two electrons are used to form bonds with the two fluorine atoms, leaving 6 electrons, which form 3 lone pairs. Therefore, the total number of electron groups is 5 (2 bonded atoms + 3 lone pairs).
Step 2: Determine the Electron Geometry
With 5 electron groups, the electron geometry is trigonal bipyramidal. This geometry accounts for the arrangement of all electron groups around the central atom.
Step 3: Determine the Bond Angle
In a trigonal bipyramidal electron geometry, the bond angles are typically 90° and 120°. However, for the linear molecular geometry of XeF\(_2\), the bond angle between the bonded atoms is 180°.
Step 4: Determine the Number of Bonded Atoms
XeF\(_2\) has 2 bonded atoms, which are the two fluorine atoms.
Step 5: Determine the Molecular Geometry
The molecular geometry of XeF\(_2\) is linear. This is because the three lone pairs occupy equatorial positions in the trigonal bipyramidal arrangement, forcing the two fluorine atoms to be opposite each other, resulting in a linear shape.