Questions: Solve (z^4-25 z^2+144=0)

Solve (z^4-25 z^2+144=0)
Transcript text: Solve $z^{4}-25 z^{2}+144=0$
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Solution

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Solution Steps

To solve the equation \( z^4 - 25z^2 + 144 = 0 \), we can use a substitution method. Let \( u = z^2 \), which transforms the equation into a quadratic form: \( u^2 - 25u + 144 = 0 \). We can then solve this quadratic equation for \( u \) using the quadratic formula. Once we find the values of \( u \), we substitute back to find the values of \( z \).

Step 1: Substitute and Transform the Equation

To solve the equation \( z^4 - 25z^2 + 144 = 0 \), we first perform a substitution. Let \( u = z^2 \). This transforms the original equation into a quadratic equation in terms of \( u \):
\[ u^2 - 25u + 144 = 0 \]

Step 2: Solve the Quadratic Equation

We solve the quadratic equation \( u^2 - 25u + 144 = 0 \) using the quadratic formula:
\[ u = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
where \( a = 1 \), \( b = -25 \), and \( c = 144 \). Solving this gives us the solutions:
\[ u = 9 \quad \text{and} \quad u = 16 \]

Step 3: Solve for \( z \)

Substitute back to find \( z \) using \( z^2 = u \). For each value of \( u \):

  • If \( u = 9 \), then \( z^2 = 9 \). Solving for \( z \) gives:
    \[ z = \pm 3 \]

  • If \( u = 16 \), then \( z^2 = 16 \). Solving for \( z \) gives:
    \[ z = \pm 4 \]

Final Answer

The solutions for \( z \) are:
\[ \boxed{-4, -3, 3, 4} \]

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