To solve the equation \( z^4 - 25z^2 + 144 = 0 \), we can use a substitution method. Let \( u = z^2 \), which transforms the equation into a quadratic form: \( u^2 - 25u + 144 = 0 \). We can then solve this quadratic equation for \( u \) using the quadratic formula. Once we find the values of \( u \), we substitute back to find the values of \( z \).
Step 1: Substitute and Transform the Equation
To solve the equation \( z^4 - 25z^2 + 144 = 0 \), we first perform a substitution. Let \( u = z^2 \). This transforms the original equation into a quadratic equation in terms of \( u \):
\[ u^2 - 25u + 144 = 0 \]
Step 2: Solve the Quadratic Equation
We solve the quadratic equation \( u^2 - 25u + 144 = 0 \) using the quadratic formula:
\[ u = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
where \( a = 1 \), \( b = -25 \), and \( c = 144 \). Solving this gives us the solutions:
\[ u = 9 \quad \text{and} \quad u = 16 \]
Step 3: Solve for \( z \)
Substitute back to find \( z \) using \( z^2 = u \). For each value of \( u \):
If \( u = 9 \), then \( z^2 = 9 \). Solving for \( z \) gives:
\[ z = \pm 3 \]
If \( u = 16 \), then \( z^2 = 16 \). Solving for \( z \) gives:
\[ z = \pm 4 \]
Final Answer
The solutions for \( z \) are:
\[ \boxed{-4, -3, 3, 4} \]