Questions: Part A Consider this balanced chemical equation: H2O2(aq) + 3 I^-(aq) + 2 H+(aq) → I3^-(aq) + 2 H2O(l) In the first 10.0 seconds of the reaction, the concentration of I^- drops from 1.170 M to 0.810 M. Calculate the average rate of this reaction in this time interval. Express your answer with the appropriate units. The value should be entered as a single number or in scientific notation.

Part A

Consider this balanced chemical equation:

H2O2(aq) + 3 I^-(aq) + 2 H+(aq) → I3^-(aq) + 2 H2O(l)

In the first 10.0 seconds of the reaction, the concentration of I^- drops from 1.170 M to 0.810 M. Calculate the average rate of this reaction in this time interval. Express your answer with the appropriate units.

The value should be entered as a single number or in scientific notation.

Transcript text: Part A Consider this balanced chemical equation: \[ \mathrm{H}_{2} \mathrm{O}_{2}(\mathrm{aq})+3 \mathrm{I}^{-}(\mathrm{aq})+2 \mathrm{H}^{+}(\mathrm{aq}) \rightarrow \mathrm{I}_{3}^{-}(\mathrm{aq})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \] In the first 10.0 seconds of the reaction, the concentration of $\mathrm{I}^{-}$drops from 1.170 M to 0.810 M . Calculate the average rate of this reaction in this time interval. Express your answer with the appropriate units. The value should be entered as a single number or in scientific notation. Submit Previous Answers Request

Solution

Solution Steps

Step 1: Calculate the change in concentration of I⁻

The change in concentration of I⁻ is the final concentration minus the initial concentration:

Δ[I⁻] = 0.810 M - 1.170 M = -0.360 M

Step 2: Calculate the change in time

The change in time is given as 10.0 seconds. Δt = 10.0 s

Step 3: Calculate the average rate of reaction

The average rate of reaction is defined as the change in concentration of a reactant or product divided by the change in time. Since the concentration of I⁻ is decreasing, the rate of reaction is calculated as the negative of the change in concentration divided by the change in time. This ensures that the rate is positive.

Average rate = - (Δ[I⁻] / Δt)

Average rate = - (-0.360 M / 10.0 s)

Average rate = 0.0360 M/s