To find the maximum revenue for the given revenue function \( R(x) = 170x - 0.80x^2 \), we need to determine the vertex of the parabola represented by this quadratic function. The vertex form of a quadratic function \( ax^2 + bx + c \) gives the x-coordinate of the vertex as \( x = -\frac{b}{2a} \). Once we find this x-coordinate, we can substitute it back into the revenue function to find the maximum revenue.
The revenue function is given by
\[
R(x) = 170x - 0.80x^2.
\]
To find the maximum revenue, we need to determine the x-coordinate of the vertex of the parabola. The formula for the x-coordinate of the vertex is
\[
x = -\frac{b}{2a},
\]
where \( a = -0.80 \) and \( b = 170 \). Substituting these values, we get
\[
x = -\frac{170}{2 \times -0.80} = 106.25.
\]
Now, we substitute \( x = 106.25 \) back into the revenue function to find the maximum revenue:
\[
R(106.25) = 170(106.25) - 0.80(106.25)^2.
\]
Calculating this gives
\[
R(106.25) = 18062.5 - 9031.25 = 9031.25.
\]
The maximum revenue is
\[
\boxed{9031.25}.
\]