Questions: Solution* Using the additive rule, the probabilities are: 1. P(A ∪ D) = P(A) + P(D) - P(A ∩ D) = 6/10 + 5/10 - 2/10 = 9/10 2. P(B ∪ C) = P(B) + P(C) - P(B ∩ C) = 4/10 + 5/10 - 1/10 = 8/10
Transcript text: Solution*
Using the additive rule, the probabilities are:
1.
\[
\begin{aligned}
P(A \cup D) & =P(A)+P(D)-P(A \cap D) \\
& =\frac{6}{10}+\frac{5}{10}-\frac{2}{10}=\frac{9}{10}
\end{aligned}
\]
2.
\[
\begin{aligned}
P(B \cup C) & =P(B)+P(C)-P(B \cap C) \\
& =\frac{4}{10}+\frac{5}{10}-\frac{1}{10}=\frac{8}{10}
\end{aligned}
\]
Solution
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